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LaGrange LFO question (sorted)

[Deleted User][Deleted User]
edited March 2020 in General App Discussion

Initialise a sound in LaGrange.

My thinking is that LFO A and B should be hardwired to OSC A and OSC B respectively.

Altering the rate of LFO B, does indeed alter if the LFO of OSC B is used.

However, this does not seem to be the case with OSC A, where altering the rate of LFO A has no effect.

Can anyone confirm that LFO A is indeed hardwired to OSC A, or is there OSC or routings that this is not the case.

I obviously haven’t tried all options, but have yet to find one where I can alter the rate of LFO A to affect OSC A.

Comments

  • SamuSamu

    To my understanding the Lagrange LFO work as follows.
    Turn left for LFO A and Turn Right for LFO B...
    (The LFO labels have small A & B labels to indicate which of the LFO's gets used).

  • [Deleted User][Deleted User]

    @Samu said:
    To my understanding the Lagrange LFO work as follows.
    Turn left for LFO A and Turn Right for LFO B...
    (The LFO labels have small A & B labels to indicate which of the LFO's gets used).

    Thanks. My poor eyesight can’t see them well enough, so thought it was positive and negative. You are indeed right though when I’ve got a magnifying glass. Thanks Samu :)

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